4x^2-28x+91=8x+10

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Solution for 4x^2-28x+91=8x+10 equation:



4x^2-28x+91=8x+10
We move all terms to the left:
4x^2-28x+91-(8x+10)=0
We get rid of parentheses
4x^2-28x-8x-10+91=0
We add all the numbers together, and all the variables
4x^2-36x+81=0
a = 4; b = -36; c = +81;
Δ = b2-4ac
Δ = -362-4·4·81
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{36}{8}=4+1/2$

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